MATLAB: Simplify(~(~(x | y) & ~(y | z))) de morganlogical operationsimplifysymbols I don't understand why it is equivalent to x | y | z . Can someone please help to explain this to me? Best Answer Remember these equivalences ( De Morgan's laws ): ~(x | y) <==> ~x & ~y ~(x & y) <==> ~x | ~yThen~(~(x | y) & ~(y | z)) ==>~((~x & ~y) & (~y & ~z)) ==>~(~x & ~y) | ~(~y & ~z) ==>~~x | ~~y | ~~y | ~~z ==>x | y | y | z ==>x | y | zApplying the operations from the outside to the inside is faster:~(~(x | y) & ~(y | z)) ==>~~(x | y) | ~~(x | z) ==>x | y | y | z Related SolutionsMATLAB: Plane y=x % plane z=x,figurehold onfsurf(@(x,y) x)% plane z = yfsurf(@(x,y) y)view(3) MATLAB: Y=√(|e^x | ) Hi Gabriela,This can be written in MATLAB program as such,x = 10;y = sqrt(abs(exp(x)));The sqrt, abs, and exp functions help to perform this task.Please do place your question in english next time, as it helps majority to understand what is asked for.Thanking you.Regards,Sriram Related QuestionWhats the error in the surface plot? How to correct itCurl with symbolic vector| -1 | = 1 how to do in matlabRMSE | Invalid CharactersMatlab OR | operator not working
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