m=2T=[1 0 0; 0 (1/sqrt(2)) (1/sqrt(2))];V1=0.956V2=2.4for k=1:3 if k==1A=[ 0 1 0]; B=[0 1 1]; D=B-A; d1=m*A; for X=1:1:m+1 C=d1+D*(X-1) c=transpose(C); Vndq=T*c; Vnq=Vndq(1,1) Vnd=Vndq(2,1) d(X)=abs(V2-Vnq)+abs(V1-Vnd) L=min(d) end elseif k==2 A=[1 0 0] B=[1 0 1] D=B-A; d1=m*A; for X=1:1:m+1 C=d1+D*(X-1) c=transpose(C); Vndq=T*c; Vnq=Vndq(1,1) Vnd=Vndq(2,1) d(X)=abs(V2-Vnq)+abs(V1-Vnd) L=min(d) end else k==3 A=[1 0 1] B=[1 0 2] D=B-A; d1=m*A; for X=1:1:m+1 C=d1+D*(X-1) c=transpose(C); Vndq=T*c; Vnq=Vndq(1,1) Vnd=Vndq(2,1) d(X)=abs(V2-Vnq)+abs(V1-Vnd) L=min(d) end endend
In the above given A ,B matrices changes for every value of k and the remaining code is same for various values of k. how to use the same code for various values of k by writing the code only once which is similar for all the values of k
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