MATLAB: Showing points in 2D map.

center of circlecircle

How to plot these four points in 2D.

T1 = [0.000, 0.000]; T2 = [67.624, -0.232]; T3 = [66.966, -67.904]; T4 = [-0.494, -67.230];

If these points are in the circumference of a circle, how to find the center and how to move center into (0, 0)?

Best Answer

Finding the centre and radius is trivial:

T0 = [T1; T2; T3; T4];
C = mean(T0);                                                   % Circle Centre
R = mean(hypot(T0(:,1)-C(1), T0(:,2)-C(2)));                    % Circle Radius

I leave the rest to you.

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MATLAB: Putting two circles on the same image

Try the following

function [outimg] = CircleIm(radius)
SizeX = 256;
SizeY = 256;
[C, R] = meshgrid(1:SizeX, 1:SizeY);
centerX = 64;
centerY = 64;
centerX1 = 192;
centerY1 = 192;
circle = (R - centerY).^2 + (C - centerX).^2 <= radius.^2;
circle1 = (R - centerY1).^2 + (C - centerX1).^2 <= radius.^2;
circles = circle|circle1;
outimg=image(circle|circle1);
colormap([0 0 0.4; 1 1 1]);
end

your method of hold on will make draw the new image on top of the last image. You need to or both images together to retain both circles. The following are drawn with a radius of 20.

MATLAB: How to draw a circle in a log-log plot

Use the FAQ to draw a circle, then exponentiate:

http://matlab.wikia.com/wiki/FAQ#How_do_I_create_a_circle.3F

xCenter = 12;
yCenter = 10;
theta = 0 : 0.01 : 2*pi;
radius = 5;
x = radius * cos(theta) + xCenter;
y = radius * sin(theta) + yCenter;
xe = exp(x);
ye = exp(y);
loglog(xe, ye, 'LineWidth', 2);
axis square;
grid on;
hold on;
% Draw second circle
radius = 3;
x = radius * cos(theta) + xCenter;
y = radius * sin(theta) + yCenter;
xe = exp(x);
ye = exp(y);
loglog(xe, ye, 'LineWidth', 2);

Best Answer

Related Solutions

MATLAB: Putting two circles on the same image

MATLAB: How to draw a circle in a log-log plot

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