MATLAB: Showing only 2 decimals

decimalsroundingsprintf

Hi guys

Trivial question, I am sure, but I can't figure this one out: I am rounding numbers to show only two decimals by:

sprintf('%.2f',number)

This doesnt work for values on the order of 1e^{-n} where n is large. The result then becomes 0.00. How do I preserve the knowledge of 1e^{-n} while still only showing two decimals?

Cheers!

Best Answer

Is this what you want?

sprintf('%.2e',0.123456789e-10)
ans =
1.23e-11

Related Solutions

MATLAB: Decimal

This is a user defined function available on the FEX: round2dp.

To use it, you have to download it and then add to MATLAB the path where you unzip it. In MATLAB File > Set path

MATLAB: I am writing a script to convert decimal to floating point binary IEEE754. However, the answer returned number binary values (e.g. 1009999900).

You cannot acurately store a decimal number greater than flintmax (~9e15) as double. Any integer above that will be rounded to the nearest decimal representable as double. So neither your bit23 (max.value > 1e23) and certainly not your output (max.value > 1e64) can be acurately stored as double.

Even as uint64, the maximum value that can be stored ( intmax('uint64'))is about 1e19, so still not enough.

My suggestion, store your bits as a vector of 0 and 1 or as a char vector of '0' and '1', e.g.:

bit23 = zeros(1, 23);   %bit8 = zeros(1, 8)
for n = 1:23
  bit23(n) = fix(fraction);   %bit8(n) = rem(exp_127,2);
  %...
fprintf('%d', [sign, fliplr(bit8), fliplr(bit23)])

Best Answer

Related Solutions

MATLAB: Decimal

MATLAB: I am writing a script to convert decimal to floating point binary IEEE754. However, the answer returned number binary values (e.g. 1009999900).

Related Question