MATLAB: Rise time fs meaning

simulink

In the Bilevel measurement parts of the scope, what does "fs" mean in terms of the rise time? My current rise time is 5.1 fs.

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A wild guess: femtoseconds?

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MATLAB: Rise/fall time

%set-up parameters
fs=44100; %CD quality - also conveniently divisible by 30 and 25
stim_dur=.025; %duration in seconds
ISI_dur=.030; %ISI duration in seconds
ramp_dur=.010; %ramp duration in seconds
t=0:1/fs:stim_dur-1/fs;
f1=500;
f2=1000;
%create signals
xt1=sin(2*pi*f1*t);
xt2=sin(2*pi*f2*t);
%setup ramp
rampSamps = floor(fs*ramp_dur);
window=hanning(2*rampSamps)'; %hanning window is cosine^2 this will change depending on the kind of ramp you want
w1=window(1:ceil((length(window))/2)); %use the first half of hanning function for onramp
w2=window(ceil((length(window))/2)+1:end); %use second half of hanning function of off ramp
w1 = [w1 ones(1,length(xt1)-length(w1))];
w2 = [ones(1,length(xt1)-length(w2)) w2];
%ramp stimuli
xt1_ramped = xt1.*w1.*w2; 
xt2_ramped = xt2.*w1.*w2; 
%generate ISI
ISI=zeros(ISI_dur*fs,1);
%final stimulus
out=[xt1_ramped';ISI;xt2_ramped'];
plot(out)

MATLAB: Accurate rise time with stepinfo()

From the documentation for stepinfo:

RiseTime — Time it takes for the response to rise from 10% to 90% of the steady-state response.

If you want the time constant τ use step with this calling syntax:

[y,tOut] = step(sys)

then interpolate (if necessary) to get the time constant:

g = tf([0 0 5000],[1 200 5000]);
[y,tOut] = step(g); 
tau = interp1(y, tOut, exp(-0.5))

producing:

tau =
   0.038246779260296

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MATLAB: Rise/fall time

MATLAB: Accurate rise time with stepinfo()

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