i have this matrix 00001110000 00001110000 00001110000 and i want to make it like that
111000000001110000000011100000000how to do that?
thanks!
MATLAB: Reshape matrix
matrixreshape
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Well you could use blockproc() to march along the data one element at a time and replacing the output block with the number of zeros specified in the input block in random locations. This requires the Image Processing Toolbox. Essentially it's
outputMatrix = blockproc(outputMatrix,[windowSize windowSize], myFilterHandle)A full demo is attached.
A =
4 2 1 4 1
4 4 4 2 4
1 3 3 4 2
1 4 4 4 2
outputMatrix =
1 1 1 1 0 0 1 1 0 0
1 1 0 0 0 1 1 1 0 1
1 1 1 1 1 1 0 1 1 1
1 1 1 1 1 1 1 0 1 1
1 0 1 1 1 1 1 1 1 1
0 0 1 0 0 1 1 1 0 0
0 0 1 1 1 1 1 1 0 1
1 0 1 1 1 1 1 1 1 0
Note how each 2x2 block of the output array has as many 1's in it as the corresponding number in the input array A.
Modified FOR loop for speed...
N = 5; X = false(N); for ii = 1:N X(ii,a(ii):b(ii)) = 1; end X = double(X); % Convert to double.
Note that if logicals will work for your application, then the last line is not needed.
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EDIT In response to your extra request for a vectorized solution.
X2 = zeros(N,N);C = b-a+1;R = zeros(1,sum(C));R([0;cumsum(C(1:N-1))]+1) = 1;C = arrayfun(@colon,a,b,'un',0); % Or try MCOLON
C = [C{:}]; % Not necessary with MCOLON
X2(cumsum(R)+(C-1)*N) = 1;MCOLON might speed up the call to ARRAYfUN. Using ARRAYFUN as above, this is much slower than the FOR loop for 5000-by-5000 X (N=5000), and occasionally runs out of memory. I tested the above using:
N = 5000;a = ceil(rand(N,1)*N);b = min(a+round(rand(N,1)*N),N);
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