Let's say I have the following cell matrix that contains NaN's, numbers, and strings…
A = {... 0 2 'All' NaN NaN 2 NaN NaN NaN NaN NaN NaN NaN NaN 'Yes' NaN NaN 1};
Is there an easy way to identify the rows and columns that contain all NaN's? In this example, I would like to remove row 2, and then columns 4 and 5. The result would be…
B = {... 0 2 'All' 2 NaN NaN 'Yes' 1};
I have brute-forced it by checking every value, but I'm sure there is a more methodical approach using cellfun perhaps. My method took 30 lines but I'm guessing there it can be done in just a few lines.
Thanks!
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