How to remove elements of a={[1 2] [3] [1 5 2] [2] [ 44 5 66 1 2]} based on d=[1 2]. the answer should be c={[] [3] [5] [] [44 5 66]}
Thanks
Best Answer
One time again:
a = {[1 2] [3] [1 5 2] [2] [ 44 5 66 1 2]};
remove = [1, 2];
for ia = 1:numel(a)
a{ia} = setdiff(a{ia}, remove, 'stable');
end
Or:
for ia = 1:numel(a)
a{ia} = a{ia}(~ismember(a{ia}, remove));
end
or many other methods. Start at reading the documentation ofsetdiff:
doc setdiff
Then proceed with the "See also" line, which shows yousimilar commands. Read the Getting Started chapters also. And study the many examples of solutions provided to your questions in the forum. If such solutions use 3 lines of code only, I'm convinced that you can try to program this by your own.
Best Answer