MATLAB: Radiation and convection in thermal models with different ambient and sink temperatures

heat transferPartial Differential Equation Toolboxpdetoolboxradiation

Dear Community,

I have to implement a simple 2D steady heat conduction problem for a rectangular domain with different boundary conditions: fixed temperature on one side, perfectly insulated on another side, convection AND radiation on the other two sides.

I have already found the solution here

https://it.mathworks.com/matlabcentral/answers/479465-radiation-in-pde-thermal-model

but it seems that it works only if BOTH ambient and sink temperatures are the same (the ambient or undisturbed temperature is applied to convection and sink temperature to radiation).

In my case these two temperatures are different. Is it possible to solve it ?

Thanks in advance!

Best Answer

To pass additional parameter, wrap the functions that actually computes with the ones you specify as inputs. In your example:

...
h = 50;     % Convective heat transfer coefficient [W/m^2 K]
sigma = 5.670367E-8; % Stefann-Boltzmann constant [W/(m^2 K^4)]
Tinf = 25;   % External fluid temperature [°C]
Ts = 15;     % External sink temperature [°C]
emiss = 0.7; % Surface emissivity [-]
mygfunInterface = @(location,state) mygfun(location,state,h,sigma,Tinf,Ts,emiss)
...

Similaraly for q functionction and use

applyBoundaryCondition(Fin,'neumann','edge',[1 3],...
    'q',myqfunInterface,'g',mygfunInterface,'Vectorized','on');

And, updated the actual function to take additinal inputs:

function bcMatrix = mygfun(location,state,h,sigma,Tinf,Ts,emiss)
...
end

Related Solutions

MATLAB: How can get the value for each time step for a variable inside of a function

Hi,

you try this code (all in one file as nested function). The values you want to have in every iteration are now added to the solution and also saved in the results table. This should be what you want.

Result = main
function Result = main
%Initial conditions
Wads=0.045;
Tads=80;
Wdes=0.035;
Tdes=27;
Teva=7;
Tcond=27;
Mweva=0.65;         
Initial=[Wads Tads Wdes Tdes Mweva Teva Tcond 0 0 0 0];           
tspan=[1:1:800];
opts = odeset('RelTol',1e-6,'AbsTol',1e-6);
[t,Soln]=ode45(@(t,Soln)ODEdw(t,Soln),tspan,Initial,opts);
colNames = {'Time','Wads','Tads','Wdes','Tdes','Mweva', 'Teva','Tcond',...
    'Tcwaout', 'Thwdout', 'Tchwout', 'Tcwcout'};
Result = array2table([tspan',Soln],'VariableNames',colNames);
function [dYdt] =ODEdw(~,Soln)
Ea=4.2*10^4;         %Activation energy of surface diffusion, (J/mol)
R=8.314;             %Ideal gas constant, (j/mol.K)
Dso=2.54*10^-4;       %Pre-exponential constant, (m^2 S^-1)
Qs=2.8*10^6;         %Heat of adsorption, (J/kg)
%%%%%%%%%%%Operating conditions%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Thwdin=85;            %Inlet temperature of hot water in desorber, (oC)
Tcwain=27;            %Inlet temperature of cooling water in adsorber, (oC)
Tcwcin=27;            %Inlet temperature of cooling water in condenser, (oC)
Tchwin=14;            %Inlet temperature of chilling water in evaporator, (oC)
mcwa=8/60;            %Mass flow rate of cooling water in adsorber, (kg/s)
mcwc=20/60;           %Mass flow rate of cooling water in condenser, (kg/s)
mchw=1.6/60;          %Mass flow rate of chilling water in evaporator, (kg/s)
mhwd=7/60;            %Mass flow rate of hot water in desorber, (kg/s)
%%%%%%%%%Physical and thermal properties of adsorbent%%%%%%%%%%
Cps=924;              %Specific heat capacity of silica gel, (J/kg.K)
Ms=9;                 %Mass of silica, (kg)
Rp=5.6*10^-4;         %Radious of silica gel particle, (m)
ps=700;              %density of silica gel, (kg/m^3)
Por=0.3;              %Porosity of silica gel,
%%%%%%Physical and thermal properties of adsorbate%%%%%%%%%%%%%
Cpw=4200;             %Specific heat capcity of water, (J/kg.k)
Cpv=1900;             %Specific heat capacity of water vapor (J/kg.K)
M=18.02;              %Molar mass of water, (g/mol)
Lv=2500*10^3;         %Lantent heat of vaporization (J/kg) 
%%%%%%%%%Physical and thermal Properties of Condenser%%%%%%%%%%%%%
Acond=5.76;            %Surface area of condenser, (m^2)
Mhexcond=19.87;        %Mass of heat exchanger (Condenser), (kg)
Ucond=486.87;          %Heat transfer coefficient of condenser, (W/m^2.K)
UAcond=Acond*Ucond;
Mwcond=1.0;         %Mass of water in Condenser (kg)
%%%%%%%%%%Physical and thermal properties of adsorber/desorber   %%%%%%%
Mhex=65;             %Mass of heat exchanger (Adsorber/desorber), (kg)
Cphex=386;           %Heat capacity of heat excahgner, (J/kg.K)
Aad=2.11;            %Surface area of adsorber/desorber, (m^2)
Uads=189.60;         %Heat transfer coefficient of adsorber, (W/m^2.K)
Udes=203.99;         %Heat transfer coefficient of desorber, (W/m^2.K)
UAads=Aad*Uads;
UAdes=Aad*Udes;
Vt=0.5;              %volume of adsorber/desorber tank, (m^3)
%%%%%%%%%Physical and thermal Properties of Evaporator%%%%%%%%%%%%%%
Aeva=0.34;           %Surface area of evaporator, (m^2)
Mhexeva=16.1;        %Mass of heat exchanger (Evaporator), (kg)
Ueva=302.58;         %Heat transfer coefficient of evaporator, (W/m^2.K)
UAeva=Aeva*Ueva;
Wads=Soln(1);    
Tads=Soln(2);  
Wdes=Soln(3);    
Tdes=Soln(4);
Mweva=Soln(5);
Teva=Soln(6);
Tcond=Soln(7);
Kads=((15*Dso)/(Rp).^2)*exp(-Ea/(R*(Tads+273.16)));   %Overall mass tarsnfer coeffcient of adsorber

Pwa=133.32*exp(18.3-(3820/((Teva+273.16)-46.1))); % Saturated vapour pressure of waterm (vapour) at adsorbent temperature, (Pa)

Psga=133.32*exp(18.3-(3820/((Tads+273.16)-46.1))); % Saturated vapour pressure of water at adsorbent temperature, (Pa)

Weqa=0.346*(Pwa/Psga)^0.625;
Aads=(Kads*(Weqa-Wads));
TLads=(Ms*(Cpw+Cpw*Wads)+Mhex*Cphex); %Left hand side of adsorber equation
Tcwaout=Tads+(Tcwain-Tads)*exp((-UAads)/(mcwa*Cpw));
   
Kdes=((15*Dso)/(Rp).^2)*exp(-Ea/(R*(Tdes+273.16)));   %Overall mass tarsnfer coeffcient of adsorber
Pwd=133.32*exp(18.3-(3820/((Tcond+273.16)-46.1))); % Saturated vapour pressure of waterm (vapour) at adsorbent temperature, (Pa)
Psgd=133.32*exp(18.3-(3820/((Tdes+273.16)-46.1))); % Saturated vapour pressure of water at adsorbent temperature, (Pa)
Weqd=0.346*(Pwd/Psgd)^0.625;
Ades=(Kdes*(Weqd-Wdes));
TLdes=(Ms*(Cps+Cpw*Wdes)+Mhex*Cphex); %Left hand side of desorber equation
Thwdout=Tdes+(Thwdin-Tdes)*exp((-UAdes)/(mhwd*Cpw));
  
TLeva=(Mweva*Cpw+Mhexeva*Cphex); %Left hand side of evaporator equation

Tchwout=Teva+(Tchwin-Teva)*exp((-UAeva)/(mchw*Cpw));
  
TLcond=(Mwcond*Cpw+Mhexcond*Cphex); %Left hand side of evaporator equation
Tcwcout=Tcond+(Tcwcin-Tcond)*exp((-UAcond)/(mcwc*Cpw));
dYdt=[Kads*(Weqa-Wads);((Qs*Ms*Aads)+(Ms*Cpv*Aads*(Teva-Tads))+mcwa*Cpw*(Tcwain-Tcwaout))/TLads;
    Kdes*(Weqd-Wdes); ((Qs*Ms*Ades)+(mcwa*Cpw*(Thwdin-Thwdout)))/TLdes; 
    -Ms*((Kads*(Weqa-Wads))+(Kdes*(Weqd-Wdes)));((-Lv*Ms*Aads)+Ades*Ms*Cpw*(Tcond-Teva)+mchw*Cpw*(Tchwin-Tchwout))/TLeva;
    (Ades*Ms*Cpv*(Tdes-Tcond)+(Lv*Ms*Ades)+mcwc*Cpw*(Tcwcin-Tcwcout))/TLcond; Tcwaout; Thwdout; Tchwout; Tcwcout];
end
end

Best regards

Stephan

MATLAB: Failure in initial objective function evaluation. FSOLVE cannot continue.

In thefunct() you confuse T and T_S and T_s

Also, the line

    T_s = T-273.15;             %convert to celsius

You need to save all of the values, such as

    T_S(i) = T-273.15;             %convert to celsius

Best Answer

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MATLAB: How can get the value for each time step for a variable inside of a function

MATLAB: Failure in initial objective function evaluation. FSOLVE cannot continue.

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