Hello ZC,
They are equivalent. In Matlab
cdf = e^z / (1+e^z)
pdf = (1/(sigma*x))*e^z / (1+e^z)^2
where
z = (log(x)-mu)/sigma
When you make the substitution (as mentioned in wikipedia, where they use s in place of sigma)
beta = 1/sigma e^mu = alpha
then
e^z = (x/alpha)^beta
and for wiki,
cdf = (x/alpha)^beta) /(1+(x/alpha)^beta)
pdf = (beta/alpha)*(x/alpha)^(beta-1)/(1+(x/alpha)^beta)^2
Best Answer