MATLAB: Problem with workspace matlab 2020b

MATLABworkspace

I have a problem with workspace ı can not see variables while code is working perfectly also ı can not see any plotting

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The code you posted is a function. Local variables for a function disappear after the function returns; you would have to put in a breakpoint before the end of the function to see the local variables.

Your posted code does not plot anything.

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MATLAB: Hi, the following code calculate true but cant plot the functions, why ? . Not this code display error : Error using mesh (line 75) Data dimensions must agree. Error in bispectwPARZENEWINDmod (line 82) mesh(w1,w2,fn); please help me

[w1,w2]=meshgrid(0:pi/20:pi,0:pi/20:pi);

w1 and w2 are going to be 21 x 21 regardless of the inputs.

NP1=NP+1;

NP1 is going to be 1 more than the input value NP.

for i1=1:NP1
for i2=i1:NP1

i1 and i2 both have maximum values of NP1, which is 1 more than the input value NP.

fn(i1,i2)=abs(fmod(i2,i1)./(sqrt(fhat(i1).*fhat(i2).*fhat(i1+i2-1))));
fn(i2,i1)=fn(i1,i2);

i1 and i2 can both go as high as NP1, so fn will be NP1 by NP1, where NP1 is 1 more than the input value NP. (By the way, have you considered pre-allocating fn ?)

mesh(w1,w2,fn);

w1 and w2 are 21 x 21 regardless of the input, but fn is NP1 x NP1 where NP1 is 1 more than the input value NP.

You will have a conflict except in the case where the input value NP is 20.

MATLAB: Automated detection of diabetic retinopathy

Hello Anas Bilal,

Code tested working on 2012.

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Related Solutions

MATLAB: Hi, the following code calculate true but cant plot the functions, why ? . Not this code display error : Error using mesh (line 75) Data dimensions must agree. Error in bispectwPARZENEWINDmod (line 82) mesh(w1,w2,fn); please help me

MATLAB: Automated detection of diabetic retinopathy

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