MATLAB: Position of the left nearest one value in a vector

indexvector

I have a vector of ones and zeros of this form: v = [0 0 1 0 0 0 1 1 1 1 0 0 1 1 0 0 0 0 0 1 0];

how can I get a vector with the left nearest zero from the one values, so that the output x is:

v = [0 0 1 0 0 0 1 1 1 1 0 0 1 1 1 0 0 1 0];

x = [0 0 2 0 0 0 6 6 6 6 0 0 12 12 12 0 0 17 0];

I am shamelly blocked so any hint to at least how to begin with would be very much appreciated.

Best Answer

I don't know what you mean by shamely blocked.

It's not a trivial one though.

x=v;
Start=strfind([0,v==1],[0,1]);
End=strfind([v==1,0],[1,0]);
x(v==1)=repelem(Start-1,diff([Start;End+1]))

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MATLAB: If I have a logical array with 2 or more sets of continuous true values, how to just grab the first or second continual set, for example

v   = [0 0 0 1 1 1 1 0 0 0 1 1 0 0];
ini = strfind(v, [0, 1]);
fin = strfind(v, [1, 0]);
idx = (ini(1) + 1):fin(1)

Or perhaps:

ini = find(v, 1);
fin = strfind(v, [1, 0]);
idx = ini:fin(1)

MATLAB: How to add 5 seconds to the output of the CLOCK function in MATLAB 7.9 (R2009b)

To do this, you can use the DATENUM and DATEVEC function as an intermediaries:

     second = [0 0 0 0 0 1];
     datevec(datenum(clock + 5* second))

You can extend this idea to perform any arbitrary day arithmetic:

     year = [1 0 0 0 0 0];
     month = [0 1 0 0 0 0];
     day = [0 0 1 0 0 0];
     hour = [0 0 0 1 0 0];
     minute = [0 0 0 0 1 0];
     second = [0 0 0 0 0 1];
     datevec(datenum(clock + 5*second + 4*month + 3*hour + 13*year));

Best Answer

Related Solutions

MATLAB: If I have a logical array with 2 or more sets of continuous true values, how to just grab the first or second continual set, for example

MATLAB: How to add 5 seconds to the output of the CLOCK function in MATLAB 7.9 (R2009b)

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