MATLAB: Plot a graph with linspace

linspaceMATLAB

Hi guys,

I want to plot this graph with Linspace,

This is what i got;

t = linspace(0,3,4)
u = [1 1 0 0]
plot(t,u)

Best Answer

You can't get that exact plot with linspace. I've managed to get it by using

t = [0 1 1 2 3];
u = [1 1 0 0 0];
plot(t, u, 'k-')

which gets the plot you want. To make the plot exactly you need to have two u values for t=1, hence the way I defined it. Linspace assigns one value to each position, so you won't get the vertical line you want.

You could make an approximation by using lots of values - something like

t = linspace(0, 3, 1000);
u = (t < = 1);
plot(t, u, 'k-')

I've used 1000 data points, the more you use the closer it will appear to what you want.

Related Solutions

MATLAB: Find intersection point between u(t) = t^2(t-1) and u = 10.

Simply use the function you calculated:

>> t_sol = vpasolve(uSol == 10,t)
 
ans =
 
                                         2.5445115283879060011505370208062
 - 0.77225576419395300057526851040312 + 1.8258281475484665736721861577551i
 - 0.77225576419395300057526851040312 - 1.8258281475484665736721861577551i

I think you can withdraw the complex solutions and the result looks like in would work looking at the plot. Testing the solution:

 >> test_sol = uSol(t_sol(1))
 
test_sol =
 
10.0

MATLAB: There is error in x1(t)

syms t t0
u(t)=piecewise(t<t0, 0, t>=t0, 1);
x1(t)=2*u(t-1)-2*u(t-3);
T = 0:1/50:10;
X1 = double(subs(x1(T),t0,0));
plot(T, X1,'r')
hold on
r(t) = piecewise(t<t0, 0, t>=t0, t-t0);
x2(t) = r(t-(11/3))-2*r(t-(13/3));
X2 = double(subs(x2(T), t0, 0));
plot(T, X2, 'b');

Best Answer

Related Solutions

MATLAB: Find intersection point between u(t) = t^2(t-1) and u = 10.

MATLAB: There is error in x1(t)

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