MATLAB: Optimization problem – max independent given a function value

symsymbolic

Hi I have the following:

syms irr2 m_S s
irr1=0.05;
M=0.7;
n=120;
f=(symsum(1/(1+irr1)^s,s,1,n)-symsum(1/(1+irr2)^s,s,1,n)*(1+M*m_S)/(1+irr2)^m_S);

f must be equal zero

m_S is a variable

I wanna know which is the max irr2 … how can I do it?

Best Answer

http://www.mathworks.com/matlabcentral/newsreader/view_thread/341674

Related Solutions

MATLAB: How to simply add two degrees together in dms format in matlab

Read about dms2degrees

d = dms2degrees([80, 30, 44]) + dms2degrees([10, 32, 10])

MATLAB: What’s wrong with the folow expression

diff(f) would invoke f with no arguments, fetch its return value, and apply the numeric diff() function to it, where the numeric diff() function is (X(2:end) - X(1:end-1)).

If you have the symbolic toolbox, you could try

syms t
df = diff(f(t),t);
f2 = diff(df,t);
f1 = inline(char(f(t)));
df1 = inline(char(df));
df2 = inline(char(f2));

Or more directly,

syms t
ft = f(t);
df = diff(ft,t);
f2 = diff(df, t);
f1 = @f;
df1 = matlabFunction(df, 'vars', t);
df2 = matlabFunction(f2, 'vars', t);
f

Best Answer

Related Solutions

MATLAB: How to simply add two degrees together in dms format in matlab

MATLAB: What’s wrong with the folow expression

Related Question