Hi,
I would like to use a for loop for a constant value i in my diff.eq. but I don't know how to implement it. Also I would like to have the matrices X and T for al the values of i.
for i : 0.1:0.1:10 [T,X] = ode45(@fx, [0 4], [0 0]) %Can I implement i here and give the matrices X and T an index?
endfunction dx = fx(t,x) % Can I give i as an input here.
rho = 1.225; C_w = 0.3; A = 0.005; m = 0.314; C_r = 0.035; R_T = 0.7; n_0 = 378.33; i = 1; T_stall = 0.1868; r = 0.030; dx = zeros (2,1); dx(1) = x(2); dx(2) = (-T_stall * R_T * i^2 * ((1000 * x(2)/ pi ) - n_0/i)/(n_0 * r) - m * 9.81 * C_r - 0.5 * rho * A * C_w * x(2)^2)/m; % the diff. eq. with i
end
Best Answer