Hello,
i have a problem. If i want to calculate the normal logarithm with an exponent.
(log(0.5))^(1/1.55)
or
(-0.6931)^(1/1.55)
matlab results:
-0.3477 + 0.7087i
but I want an other result. If I write the equation on this way:
-0.6931^(1/1.55)
matlab results
-0.7894
Why is there a difference? The normal logarithm of 0.5 is -0.6931 and with an exponent of (1/1.55) my calculator show 0.7894 (not -0,7894 or -0.3477 + 0.7087i).
I need this (x=0.5)
(log(x))^(1/1.55)= 0.7894
Best Answer