Hello everyone!I am trying to create a function that you can put a vector 'x' and a order 'N' to solve for the exp(x). It is close to being correct however i just can't seem to get it.
function [y] = nexp1(x,N)U = length(x);for k = 1:U asum = 0; for w = 1:length(x) new = (x(k).^w / factorial(w)) asum = asum + new end y(k) = asumendend
Best Answer