MATLAB: More non-singleton rhs dimensions

singleton

I am getting an error here but I am not sure why.

I am trying to create a 1×5 matrix for the 5 c answers using the 5 t values in that matrix.

Thanks

Best Answer

I'm thinking that you want to loop through your t values. You first assign t to the vector [30,60,90,120,150] but then reassign it in your for loop to (1:5) or [1 2 3 4 5]. You instead need to index your values of t inside of your loop something like

x = (0:1:100)'
Ex = 0.02
m = 1
u = 0.5
c = zeros(101,5)
t = [30,60,90,120,150];
for k = 1:5
    c(:,k) = m/sqrt(4*pi*Ex*t(k))*exp(-(x-u*t(k)).^2)./(4*Ex*t(k))
end

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MATLAB: How can i plot a sine wave which is 5sin(2pi50t) for 20 seconds and 5sin(2pi55t) for next 30 seconds and again repeating 5sin (2pi50t)

Your title has something very different from your actual post, so I'm not sure what you actually want. And following your post, did you really want a 1 second gap with no sine wave? This does want you state in the actual body of your post.

 t = 0:1/200:50;
 x = zeros(size(t));
 x = 5*sin(2*pi*50*t).*(t<=20)+5*sin(2*pi*55*t).*(t>20);
 plot(t,x)

MATLAB: How to search row and delete row

 x= [15 30 45 60 -45 -30 0 90 15 30 45 60 -45 -30 0 90 15 45 60 -45 -30 0];
 a = unique(x);
 b = a(a ~= x(end));
 value = ones(numel(b),1)*x;
 value(:,end) = b;

Best Answer

Related Solutions

MATLAB: How can i plot a sine wave which is 5*sin(2*pi*50*t) for 20 seconds and 5*sin(2*pi*55*t) for next 30 seconds and again repeating 5*sin (2*pi*50*t)

MATLAB: How to search row and delete row

Related Question

MATLAB: How can i plot a sine wave which is 5sin(2pi50t) for 20 seconds and 5sin(2pi55t) for next 30 seconds and again repeating 5sin (2pi50t)