sir i want to implement minimization problem using simplx method can i use matrix for this and how can i iterate each time the matrix as per simplex method rule, plz any one if know tell me (my question simply tells processing of simplex method )
MATLAB: Minimization problem -using simplex method
simplex method
Related Solutions
Hi,.
try:
syms x1 x2 x3h=4;gma=18.4;ka1=0.2;kp1=8.76ka2=0.2;kp2=8.76;sindel=0.437;cosdel=0.9;pa1=ka1*gma*(h*x1+0.5*x1^2);pp1=kp1*gma*0.5*x1^2;pa2=ka2*gma*(x1*x2*+0.5*x2^2);pp2=kp2*(x2*(h+x1)+0.5*x2^2);za1=(0.5*h*x1^2+(x1^3)/6)/(h*x1+0.5*x1^2);zp2=(0.5*(h+x1)*x2^2+((x2^3)/3))/((h+x1)*x2+0.5*x2^2);za2=(0.5*x1*x2^2+((x2^3)/3))+(x1*x2+0.5*x2^2);e1=pp1*sindel-pa1*sindel-pp2*sindel-pa2*sindel;e2=pp1*cosdel+pa2*cosdel-pa1*cosdel-pp2*cosdel-x3;e3=pp1*cosdel*(x1/3)+pp2*cosdel*zp2-pa1*cosdel*za1-pa2*cosdel*za2-x3*(x1+(h/3));g=[e1; e2; e3];J=jacobian([e1, e2, e3], [x1, x2, x3])results in:
J =[ (1075457*x1)/15625 - (95703*x2)/25000 - (10051*x2^3)/12500 - 20102/3125, - (95703*x1)/25000 - (95703*x2)/25000 - (30153*x1*x2^2)/12500 - 95703/6250, 0][ (207*x2^3)/125 - (1971*x2)/250 + (88596*x1)/625 - 1656/125, (621*x1*x2^2)/125 - (1971*x2)/250 - (1971*x1)/250 - 3942/125, -1][ (44298*x1^2)/625 - x3 - (207*x2^3*(x1*x2 + (x1*x2^2)/2 + x2^2/2 + x2^3/3))/125 - (1656*x1)/125 + (x2^2*((1971*x2*(x1 + 4))/250 + (1971*x2^2)/500))/(2*(x2^2/2 + (x1 + 4)*x2)) - (((414*x1)/125 + 1656/125)*(x1^3/6 + 2*x1^2))/(x1^2/2 + 4*x1) + (1971*x2*(x2^3/3 + (x1/2 + 2)*x2^2))/(250*(x2^2/2 + (x1 + 4)*x2)) - (207*x1*x2^3*(x2^2/2 + x2))/125 + (((207*x1^2)/125 + (1656*x1)/125)*(x1^3/6 + 2*x1^2)*(x1 + 4))/(x1^2/2 + 4*x1)^2 - (x2*(x2^3/3 + (x1/2 + 2)*x2^2)*((1971*x2*(x1 + 4))/250 + (1971*x2^2)/500))/(x2^2/2 + (x1 + 4)*x2)^2, ((x2^3/3 + (x1/2 + 2)*x2^2)*((1971*x1)/250 + (1971*x2)/250 + 3942/125))/(x2^2/2 + (x1 + 4)*x2) - (207*x1*x2^3*(x1 + x2 + x1*x2 + x2^2))/125 - (621*x1*x2^2*(x1*x2 + (x1*x2^2)/2 + x2^2/2 + x2^3/3))/125 + ((2*x2*(x1/2 + 2) + x2^2)*((1971*x2*(x1 + 4))/250 + (1971*x2^2)/500))/(x2^2/2 + (x1 + 4)*x2) - ((x2^3/3 + (x1/2 + 2)*x2^2)*((1971*x2*(x1 + 4))/250 + (1971*x2^2)/500)*(x1 + x2 + 4))/(x2^2/2 + (x1 + 4)*x2)^2, - x1 - 4/3]Best regards
Stephan
Note that there are not only numbers in that string, it also contains 'S' characters apparently at random, e,g.:
>> f(8480:8500)ans =3 -118 S 623 1623 -71% ^ not digit character!
One simple and efficient solution is to remove those 'S' characters before using sscanf:
v = sscanf(strrep(f,'S',''),'%d');This correctly returns all 4297 numbers in the string, and can be easily adapted (e.g. using regexprep to remove specific types of characters, e.g. if it is possible that other alphabetic characters might occur in the string).
The simplest and most efficient solution by far is this:
v = sscanf(f,'%d%*[S ]');Nothing will beat that simple command in terms of simplicity or speed.
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