Below is a basic code of finding a root of a function using the Newton Root method. While i set the imax, which is the maximum number of iteration, the final number of iteration running this code has exactly one more than my maximum no. of iterations set. And the no. of iteration is different with the one of the model answer from my teacher. Anyone has an idea why is this? I have exam next week please help.
clear; clc; Fun=@(x)(8-4.5*(x-sin(x))); FunDer=@(x)(-4.5*(1-cos(x))); root=newtonroothaha(Fun,FunDer,2,0.0001,10)
function[Xs]=newtonroothaha(Fun,FunDer,Xest,Err,imax) oerr=100; iteration=0; while (iteration<=imax && oerr>Err) iteration=iteration+1; Xnew=Xest-(Fun(Xest)/FunDer(Xest)); oerr=abs((Xnew-Xest)/Xest); end Xs=Xnew; iact=iteration end
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