MATLAB: MATLAB miscalculates simple multiplication

miscalculation

Hello, excuse me for this question, I hope that I am not overloocking something really simple. My code is the following:
for a = 1:len
    houses{a} = data{a*3-2};
    try
        timet{a} = datetime(data{a*3-1})-startTime;
    catch error
        disp(data{a*3-1})
        disp(a*3-1)
        disp(a)
        disp(a*3)
        break
    end
    distance{a} = data{a*3};
end
The important part is the part in the catch statement. I inserted it to find the cause of my problem and let maplab display me the value for a and a*3 in the end. Matlab returns:
>> 10923
>> 32767
If I type in 10923*3 manually it returns
>> 32769
(which is the right solution)
Does anyone see where my mistake is? I'm sorry, I just can't figure it out right now. Best, Viviane

Best Answer

Your 'a' values somehow got converted to type int16, which have a maximum value of
 >> disp( intmax('int16'))
   32767
If you convert the data to double type, the problem should go away
   >> disp(double(a)*3)
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