Hey all,
Suppose you have as input: matrix A = [10 9 8] and some factor X = 3
As output i would like to obtain: R = [10 10 10 9 9 9 8 8 8]
I am wondering if there are better (faster) solutions then my solution below:
R = zeros(1,length(A)*X);for i =1:X R(1+length(A)*(i-1):1:length(A)*i) = A(i);end
Best Answer