MATLAB: Logarithmic equation with ln

equationlnlogMATLAB

Hello ,

How can i write this in matlab? I tried to read the documentation but it confuses me more. My variable b is equal to 0.174 ln(59.6 rf /rs). Any ideas?

Thank you!

Best Answer

b = 0.174 * log( 59.6 * rf ./rs )

Related Solutions

MATLAB: Maclaurin series for ln(x) and ln(x+1)

Maclaurin series is just a Taylor series expanded at x = 0. For ln(x) the series does not exist. For ln(1+x), try the following

syms x
y = log(x + 1);
y_series = taylor(y, x, 0, 'Order', 10)

MATLAB: Solving a system of 7 equations with solve is producing empty solutions, any ideas

It is capable of solution, at least if you switch to rational values. The solution set is

g2 = (343589772257/5618160000) * ln(4/25) + (2143806607181/1872720000) * ln(21/25) + (21133190640089/1755675000) * ln(37/40) - (95870309503/585225000) * ln(3/40)
g1 = -(919857962803/877837500) * ln(4/25) + (12238047735179/1170450000) * ln(21/25) + (3446099474468/1097296875) * ln(37/40) + (194094869444/365765625) * ln(3/40)
gp2 = (150541236341/33379500) * ln(4/25) - (3258413397883/76296000) * ln(21/25) + (14648669392/5960625) * ln(37/40) - (14648669392/5960625) * ln(3/40) + (45875/15708) * g1
gp1 = gp2
Lo = -(61079719697/4492080) * ln(4/25) + (61079719697/4492080) * ln(21/25) + (31651589222/7018875) * ln(37/40) - (31651589222/7018875) * ln(3/40) + (255/367) * gp1
L1 = -(200/51) * Lo - (261583382/7803) * ln(4/25) + (261583382/7803) * ln(21/25) + (261583382/7803) * ln(37/40) - (261583382/7803) * ln(3/40)
A1 = (130791691/10000) * ln(4/25) - (130791691/10000) * ln(21/25) - (130791691/10000) * ln(37/40) + (130791691/10000) * ln(3/40)

Best Answer

Related Solutions

MATLAB: Maclaurin series for ln(x) and ln(x+1)

MATLAB: Solving a system of 7 equations with solve is producing empty solutions, any ideas

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