I have a "x1c" cell, and with the following code:
tn=1for N=1:6591 for t=1:200 k=(((abs(x1c{t,1}(N)-x1c{1,1}(N))).^2))/(6591*200*6) tn=tn+1; endend
I would like to take the "limit of the "k" while t goes infinity"; is it possible?
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