MATLAB: Keep on getting ‘Error using plot, Vectors must be the same length’. How to plot it correctly

plotplottingwhile loop

t(1) = 0; %Time, seconds
T(1) = 0; %Thrust, Newtons
m = 85/1000; % mass, grams
h(1) = 0.2; %Height, meters
A_rocket = 1.2141; %Drag Area, meters^2
c_d = 0.06; %Coefficient of Drag
g = 9.81; %Gravity, meters/second^2
p = 1.225; %Air Density, kilograms/meter^3
v(1) = 0; %Velocity, meters/second
a(1) = 0; %Acceleration, meters/second^2
W = 0.324; %Weight, Newtons
%%
i = 1; %Loop Term
h_check = h(1); %Height Check
t_step = 0.01; %Time Step Intervals
while h_check >= -0.5
    
    
    %Thrust Function
    if t(i) <= 0.22
        T(i) = 45.45*(t(i));
    elseif t(i) <= 0.27
        T(i) = -140*(t(i))+3;
    elseif t(i) <= 0.67
        T(i) = -2.5*(t(i))+3;
    elseif t(i) <= 0.72
        T(i) = -40*(t(i))+2;
    else T(i) = 0;
        break
    end
    
    a(i+1)= - m * g + T(i) - c_d * ((p * v(i).^2)/2) * 0.2 / m
    
     
     
     v(i + 1) = v(i) + a(i) * t_step
     
     h(i + 1) = h(i) + v(i) * t_step
     
     t(i+1) = t(i)+t_step;
     
     i = i + 1
    
    
end
t(end) = [];
h(end) = [];
figure
plot(t,T)
title('Time Vs. Thrust')
xlabel('Time')
ylabel('Thrust')
figure
plot(t,a)
title('Time Vs. Acceleration')
xlabel('Time')
ylabel('Acceleration')
figure 
plot(t,v)
title('Time Vs. Velocity')
xlabel('Time')
ylabel('Velocity')
figure
plot(t,h)
title('Time Vs. Height')
xlabel('Time')
ylabel('Height')

Best Answer

When the while loop breaks, you have defined T to have length of i_max, and t has length i_max+1. This is because of the line 
t(i+1) = t(i) + t_step
which causes the vector t to be one element longer than T. To be able to plot correctly, you could either drop the last element in t (since it doesn't appear to affect the last element of T) or compute a final element of T. It looks like you already thought of my first idea, so if you remove the lines
t(end) = [];
h(end) = [];
your code should work.
Edit I made some errors in my previous answer, this is corrected now.
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