MATLAB: It follows the END that terminates the definition of the function “NumIntF” error

function

function f =NumIntF(xi,xf)
h=0.001;
N=(xf-xi)/h;
ii=1;
while(ii<= (N+1))
if(ii==1);
x(ii)=xi;
y(ii)= cos(x(ii))*exp(sin(x(ii)))*h;
else
x(ii)=x(ii-1)+h;
y(ii)=y(ii-1)+cos(x(ii))*exp(sin(x(ii)))*h;
end
ii=ii+1;
end
f= y(N+1);
end

Best Answer

Put
xi = 0;
xf = pi; % or whatever your desired start and end values are.
f = NumIntf(xi,xf)
in a script and run that - it worked for me.
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