How does isletter work here. Is it the value 1 that makes it executable and the value 0 that makes it not excecute and go to else?
MATLAB: Isletter true false
isletter 1 0
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"...however if I try to apply the same command again as..."
You have failed to take into account that inbetween running these two commands you have changed the data. So while the first cell array only contained scalar numeric (which is a bad way to store numeric data), the second time you call cellfun the cell array now also contains char vectors (lots of 'false', to be precise). Of course when you compare 'false'==1 then the output will be a vector like this:
>> 'false'==1ans = 0 0 0 0 0
and that is clearly not a scalar value, so your cellfun usage will fail unless you use 'uni',false and some more complex processing, or wrap the first argument function in any or something similar. Your third example give this error message
Function 'subsindex' is not defined for values of class 'cell'
because when you use the option 'UniformOutput',false then cellfun outputs a cell array, which cannot be used for indexing. So your attempt to use the output as an index will fail.
Here is a simpler approach using a numeric array (which it should be anyway):
>> m = cell2mat(a);>> id0 = m==0;>> id1 = m==1;>> a(id0) = {'false'};>> a(id1) = {'true'};>> aa = 'false' 'true' [ 2] [ 3] [ 4] [ 5] [ 6] [ 7] [ 8] [ 9] [ 10] [ 11] 'true' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' [ 2] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 3] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 4] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 5] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 6] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 7] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 8] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 9] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 10] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' [ 11] 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'true' 'false' 'false' 'false'
Note that your row and column headers indicate that you should perhaps be using a table, or only storing the actual data (not the headers) in a simple numeric array. Then you could do this task very simply with some basic indexing:
>> c = {'false','true'};>> b = c(1+m(2:end,2:end))b = 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'false' 'false' 'false' 'false' 'true' 'true' 'true' 'false' 'false' 'true' 'false' 'true' 'false' 'false' 'false'
Jarvan,
you misused the call to input
when you use
word = input('Enter a letter and a #: ')
Matlab expects the user to give a valid expression, not a string.
what you want to do is to give a string as input, so, just do
word = input('Enter a letter and a #: ','s') % add a second argument to _input_ to consider the input as a string.
and then you can decompose the data word in two parts num and let .
Note : in your code, num and let are not calculated ?!
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