I have tried without luck to understand why i am receiving x^2 as the solution to my equation. When using 'ReturnConditions' I can see that the parameter is x. I don't see how this is the solution to the equation. The code that returns x^2 is
clearclcsyms xv Aop Btv Dop K11v K32v positivefunc = xv == Aop + (3*Btv)/2 - (3*Dop^(1/2))/(2*Aop^(3/2)*K32v^(1/2)) - (Dop^(1/2)*K11v)/(2*Aop^(1/2)*K32v^(1/2));[funcsol, funcparam, funccond] = solve(func, Aop, 'ReturnConditions', true);[funcsol, funcparam]
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