MATLAB: Is it possible to find corresponding row from other matrix’s row?

MATLAB

y = [ 90    90   -45     0     0    45    45     0   -45    15    15;
  90    90   -45     0     0    45    45     0   -45    15    15;
  90    90   -45     0     0    45    45     0   -45    15    0;
  90    90   -45     0     0    45    45     0   -45    15    0;
  90    90   -45     0     0    45    45     0   -45    15    15;
  90    90   -45     0     0    45    45     0   -45    15    15;];
    y0 = sort(y,2);
  y = y(sum([ones(size(y,1),1),diff(y0,[],2)~=0],2) >= numel(unique(y)),:);
    y = permute(y ,[3 2 1]);
 for  k = 1:size(y,3)
    [x0(:,:,k), x00(:,:,k)] = hist(y(:,:,k), unique(y(:,:,k)));
 end
 x0 =permute(x0,[3 2 1]);  x00 =permute(x00,[3 2 1]);
 x0(any(x0<2,2),:) = [];
I have to find corresponding row of "x00"

Best Answer

It is easy, you just need to assign the logical conditions to an index variable. So instead of this:
x0(any(x0<2,2),:) = [];
you should allocate that logical condition to a variable:
idx = any(x0<2,2);
and then you can use idx for any of the matrices:
>> xdel = x0(idx,:)
xdel =
   2   4   1   2   2
   2   4   1   2   2
>> xnew = x0(~idx,:)
xnew =
   2   3   2   2   2
   2   3   2   2   2
   2   3   2   2   2
   2   3   2   2   2
and now you can try x00(idx,:) and x00(~idx,:) yourself!
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