In your code:
isfield(['A.' D.E.F{i}],'C')
what is D.E.F{i}? A concatenation with 'A.' will create a char vector. Char vectors are no structs, so isfield replies false as expected.
Try this instead:
% Some test data:
A1.B.C = 1;
A2.AnyStuff = '?';
A2.FunnyName.C = 2;
A3.HasNoC.D = 3;
A3.Nonsense = {};
% TRUE if subfield is existing:
hasSubField(A1, 'C')
hasSubField(A2, 'C')
hasSubField(A3, 'C')
function T = hasSubField(S, F)
T = false;
Data = struct2cell(S);
for k = 1:numel(Data)
if isfield(Data{k}, F)
T = true;
return;
end
end
end
This searchs for a subfield in the first level. If any of the fields is a struct and contains the field provided by the input F, true is replied. Or are you searching for deeply nested structs also?
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