MATLAB: Intersection between line and circle

circleintersectionlineMapping Toolbox

Please check the image above

I need to find the intersection point of the line with the circle 3 and circle 4.

If I use linecirc() command, i get the values of circle 1 also.

Is there any other command to get the required values ?

Thanks in advance

Best Answer

Each circle with have either 0, 1, or 2 intersection points. Do you have the formula for each circle, meaning it's center coordinates and radius ? If seems like knowing the formulas for the lines you might be able to use fzero() to find the intersection point(s).

By the way, what toolbox is linecirc() in? I don't have it.

Related Solutions

MATLAB: Example of linecirc function

Hi Manoj,

linecirc gives the intersection points of a line and a circle.

Syntax:

[xout,yout] = linecirc(slope,intercpt,centerx,centery,radius);

This function finds the points of intersection given a circle defined by a center and radius in x-y coordinates, and a line defined by slope and y-intercept, or a slope of “inf” and an x-intercept. Two points are returned. When the objects do not intersect, NaNs are returned.

When the line is tangent to the circle, two identical points are returned. All inputs must be scalars.

Example:

[xout, yout]  = linecirc(-1,3,0,0,5);

This will give the intersection point of line

and circle

MATLAB: For intersecting circles, how to remove overlap and have chord visible? Also, how to randomly generate circle position in design space

How are you drawing your circles?

However you are trying to draw it you'll probably end up having x and y points representing the 2 circles.

xCenter1 = 7;
yCenter1 = 7;
xCenter2 = 12;
yCenter2 = 10;
theta = 0 : 0.01 : 2*pi;
radius1 = 5;
radius2 = 6;
%generate 2 circles with parameters above.
  x1 = radius1 * cos(theta) + xCenter;
  y1 = radius1 * sin(theta) + yCenter;
x2 = radius2 * cos(theta) + xCenter2;
y2 = radius2 * sin(theta) + yCenter2;
%%find distance from each circle center to the other circle's infringing points.
dC1 = sqrt((x2-xCenter1).^2+(y2-yCenter1).^2)>=radius1;
dC2 = sqrt((x1-xCenter2).^2+(y1-yCenter2).^2)>=radius2;
plot(x1(dC2), y1(dC2),'b.',x2(dC1),y2(dC1),'r.');
axis square;
xlim([0 20]);
ylim([0 20]);
grid on;

Looking at your sample picture it is easy to see that the infringing portion of circle 2 into circle 1 are points that are within the radius of circle 1. (vice versa for circle 2) With this we can calculate the distance of all points of circle 2 to the center of circle 1 and compare it to the radius.

Best Answer

Related Solutions

MATLAB: Example of linecirc function

MATLAB: For intersecting circles, how to remove overlap and have chord visible? Also, how to randomly generate circle position in design space

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