MATLAB: Integration of a function.

integreation

I'm trying to integrate a function but is giving be this error below
Incorrect dimensions for matrix multiplication. 
Check that the number of columns in the first matrix matches the number 
of rows in the second matrix. To perform elementwise multiplication, use '.*'.
I cant identify to set the dimention right but is still giving error. Please help me.
L=1;
T=100;
r=0.03;
I1=0.1;
p=0.1;
epsilon=0.3;
rho=1000;
beta= 0.1;
Cr=3000;
RhoP=0;
Mycp = 0:10:100; 
n = zeros(numel(Mycp),1 );
n2 = zeros(numel(Mycp),1 );
n3 = zeros(numel(Mycp),1 );
Jcp = zeros(numel(Mycp),1 );
for i = 1:numel(Mycp )
    MycpCurrent=Mycp(i);
    delta = 1-MycpCurrent/100;
    tau = (1/(beta*(L+delta*p)))*log((L*(I1+delta*p))/(delta*p*(L-I1 )));
    t05 =(1/(beta*(L+delta*p)))*log((L*(0.05*L+delta*p))/(delta*p*(L-0.05*L )));
    I2= @(t)(L*delta*p*(exp (beta*(L+delta*p)*t)-1)) ./ (L + delta*p* exp(beta*(L+delta*p)*t ));
    I3= @(t)(L*(I1+delta*p)*exp((epsilon*beta)*(L+delta*p)*(t-tau))-...
    delta*p*(L -I1))./(L-I1+(I1+delta*p)*exp(epsilon*beta*(L+delta*p)*(t-tau)));
    
    fun = @(t,MycpCurrent) MycpCurrent*L*exp(-r*t);
    fun2=@(t) rho*I2(t)*I3(t).*exp(-r*t)+((Cr*L*exp(-r*tau)));
    fun3=@(t)RhoP*I2(t)*I3(t).*exp(-r*t);
    
    n(i) = integral(@(t)fun(t,MycpCurrent),0,100, 'ArrayValued',1);
    n2(i)= integral(fun2,t05,tau); %this is giving me error.
    n3(i)= integral(fun3,tau,100);
end

Best Answer

Hello,
You just need to remove "." in the formulation of I2, I3, fun2 and fun3. The code will run withour errors.
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