Hi all,
I need to solve the following equation for each individual value of f where f=0:0.01:10:
The equation is for MSAR in the code below, with the intention of getting a range of RMSAR values for a given f.
K1=274350; C1=11040; K2=414000; C2=16000;M=13200; L1=2.34; L2=2.885; K=2.310;I=M*(K^2);a1=46.85*(10^-4); b1=0.19;syms fw=f*2*pi;B11=K1+K2-M*(w^2)+1i*w*(C1+C2);B12=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);B13=-K1-1i*w*C1;B21=K2*L2-K1*L1+1i*w*(-C1*L1+C2*L2);B22=K1*(L1^2)+K2*(L2^2)-I*(w^2)+1i*w*(C1*L1^2+C2*L2^2);B23=K1*L1+1i*w*C1*L1;B31=0; B32=0; B33=1;S1=K2+1i*w*C2;S2=K2*L2+1i*w*C2*L2;S3=0.975;B(1,1)=B11; B(1,2)=B12; B(1,3)=B13;B(2,1)=B21; B(2,2)=B22; B(2,3)=B23;B(3,1)=B31; B(3,2)=B32; B(3,3)=B33;S(1,1)=S1; S(2,1)=S2; S(3,1)=S3;T=B\S;hif=T(1,:)';G1=a1*exp((-b1)*f);MSARn=@(f)((abs(hif))^2).^(f^4)*G1;iMSARn=int(MSARn,0.89*f,1.12*f);MSAR=((2*pi)^4)*iMSARn;RMSAR=MSAR.^0.5;
When I try running the code, it's incredibly slow. I left it going over night and it still wasn't done. So I need a more practical method as this is only a section of a larger code. Am I correct in thinking that only 'int' accepts variable integral limits? I've tried 'quad' in a loop but it still sees the limits as non-scalar:
for k=1:1:1001; f(k)=(k-1)/100; iMSARn(k)=quad(@PSD_Opt_int_loop,[0.89*f(k),1.21*f(k)]);end
Thanks in advance.
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