if i have this matrix
Matrix_row = [2 4 2 0 0 3 6 0 0 0 4 5 0 0 0 1 2 2 0 0 1 2 1 1 0 1 2 2 0 0 2 3 2 0 0 2 2 2 0 0 1 1 1 4 0 10 0 0 0 0 ]
and i compute this values
a = [ 8 9 9 5 5 5 7 6 7 10 ] and b = [ 3 2 2 3 4 3 3 3 4 1 ] i need to chick like this f = zeros(10,10) for k=1:10 if a(k) + b(k)-1 == 10 if this condition true then go bake to Matrix_row(k) and convert this row to be a binary (the number in Matrix_row shows how many number of ones in this row like
[2 4 2] == [1 1 0 1 1 1 1 0 1 1]
- when the condition is true , the number in Matrix_row in that row must between the group of ones just one zero
the final solution will be
F = [ 1 1 0 1 1 1 1 0 1 1 1 1 1 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 1 0 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ]
Best Answer