MATLAB: I want to rewrite the following expression into arctan.

MATLABrewritesymbolic

Hi All,
I want to rewrite the following expression into arctan. Can anyone help?
    m=(k_1*(sin(theta1) + cos(k_1*(gama - theta1))*sin(theta0) - cos(theta0)*sin(theta1) + cos(theta1)*sin(theta0) - M*sin(theta1) - k_1*sin(k_1*(gama - theta1)) - M*cos(k_1*(gama - theta1))*sin(theta1) + k_1*cos(theta0)*sin(k_1*(gama - theta1)) + M*k_1*sin(k_1*(gama - theta1)) - M*k_1*cos(theta1)*sin(k_1*(gama - theta1))))/(M*l*(2*k_1 - sin(k_1*(gama - theta1))*sin(theta1) + 2*k_1*cos(k_1*(gama - theta1))*cos(theta1) - k_1^2*sin(k_1*(gama - theta1))*sin(theta1))) - (k_1*(M*sin(theta1) - cos(k_1*(gama - theta1))*sin(theta1) - sin(theta0) + M*cos(k_1*(gama - theta1))*sin(theta1) - k_1*cos(theta1)*sin(k_1*(gama - theta1)) + cos(k_1*(gama - theta1))*cos(theta0)*sin(theta1) - cos(k_1*(gama - theta1))*cos(theta1)*sin(theta0) - M*k_1*sin(k_1*(gama - theta1)) + k_1*cos(theta0)*cos(theta1)*sin(k_1*(gama - theta1)) + k_1*sin(k_1*(gama - theta1))*sin(theta0)*sin(theta1) + M*k_1*cos(theta1)*sin(k_1*(gama - theta1))))/(M*(2*k_1 - sin(k_1*(gama - theta1))*sin(theta1) + 2*k_1*cos(k_1*(gama - theta1))*cos(theta1) - k_1^2*sin(k_1*(gama - theta1))*sin(theta1)))

Best Answer

No, there are no log terms and no imaginary constants and no sqrt() of expressions; there is nothing to rewrite into arctan. It would make more sense to rewrite it into tan
Some of the trig calls can be combined, for whatever that is worth. That does not make it any easier to understand, and has nothing to do with rewriting to arctan.
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