MATLAB: I want to creat the loop of background substraction.

for loopimage analysisimage processingwhile loop

Hi,

I am using the simple code line to substract one picture from another as given below.

k=image1-image2;

then I will need to subtract 10 more pictures from image 1 to see the difference.

for example:

k=image1-image2;

k1=image1-image3;

k2=image1-image4;

Is there a way that I can make a loop in which all the Images (2,3,4,5,6,7….) I want will be subtracted from image1.

Best Answer

Place all images into a cell array.

for m=2:length(image)
    k{m-1}=image{1}-image{m};
end

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MATLAB: Assign a vector

variant with loop with example

Ac = randi(100,[1 5 2 2]);
D = zeros(3,3,2,2,2,2)
for k=1:K 
    for m=1:M
        C = num2cell(Ac(1,:,k,m));
        [D(1,2,2,2,k,m) D(2,1,2,2,k,m) D(1,3,2,2,k,m) D(3,1,2,2,k,m) D(2,2,2,2,k,m)] = C{:};
    end
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MATLAB: Problem with dsolve: Unable to find explicit solution

I found a way to do this, but I will need to wait until I get to my desktop to write through all of the steps as simplify() gave some unexpected results that are not understandable as-is.

The approach is to notice that the last sub-expression of the first two equations is the same as the expression for Dc. The first two are like Da=P+Dc , Db=-P+Dc in form. Select down to those two with the sub-expression replaced by Dc and dsolve. You will get solutions for a and c.

Take the expression for c and substitute t=0 to get c(0). You will get an expression in C1, C2, and some other terms and you know that c(0)=0 so solve() the expression for C2. The result will involve b(0) but we know that b(0)=0 so subs() that to get C2.

Now subs that C2 into the solution for a. subs t=0, solve() that equal 0.26 for C1, subs b(0)=0 and you get out C1

Now go back to the solutions for a and c and substitute in C1 and C2 and b(0)=0 to get the final a and c. Do not simplify() c!!! -- you will get weird results if you do!

Those in hand, go back to the second equation giving the expression for Db and substitute a and c and derivative of c to get Db.

At this point I simplify() and the dB term disappeared, and it was then that I noticed unexpected functions in the output, which I traced back to my having simplify() after I subs C1 into c. So at the moment I do not have the final production for b, but it should be down to a single equation and b(0)=0 will clearly be important. This resolution will have to wait until I get to my desktop.

Best Answer

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MATLAB: Assign a vector

MATLAB: Problem with dsolve: Unable to find explicit solution

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