This is my main code:
clc clearf=3500;cd=.6;cf=3;m0=600;c=2;d=0;dN=0;for t=0:0.1:5 vE=0; m=m0-(c*t); n=0; v=0; a=(f/m)-((cd/m)*v); vE=vE+(a*.1); fprintf('VEuler is %1.2f when t is %1.1f \n',vE,t) vO=v+vE; dN=((5+t)*((vO+vE)/2))+d;endfprintf('After initiating acceleration, the dragster has moved %1.2f meters\n',dN)y0 = 0;tspan=0:0.1:5;[t,y]= ode45('fun',tspan,y0);fprintf('\n t y\n');tvalues=transpose(t);fxvalues=transpose(fx);
With the function:
function fx=fun(t,y0)global f cd cf m0 c;fx=(((cf/m0-c.*t))*y0)-((cd/m0-c.*t).*y0.^2)+(f/m0-c.*t);end
Matlab is telling me that it's returning a vector length of zero, an ode arguements error (odearguments(FcnHandlesUsed, solver_name, ode, tspan, y0, options,varargin);)
and that there's an error in the ode function itself. I've explored the internet and tried several online solutions but none have worked.
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