MATLAB: I have the equation: sin(x)=cos(2x^2), [0,2]

write a fuction

How do I put this in as a matlab code to find four startvalues for x0. I know how to make regular functions, but cannot fin where to make this work

Best Answer

syms x ;
eqn = sin(x)-cos(2*x^2)==0 ;
sol = solve(eqn,x)

Related Solutions

MATLAB: How to solve this integration ???

This shows that MATLAB is not able to find a closed-form expression for the integration problem. You can still find the numerical answer by substituting the numeric values of a and b

syms x a b
c = (x*cos(x)*sin(x))/(a^2*cos(x)^2 + b^2*sin(x)^2)^2;
c_int = int(c, x, 0, pi/1);
x = subs(c_int, [a b], [1 2]);

This will give the value of integration at a=1, b=2. Result:

>> x
x =
-pi/12

MATLAB: Undefined variable “cos” or class “cos”. Error in P4Afara_Question2 (line 5) z = (cos(x)).cos(sqrt(x.^2 + y.^2)).exp(-1abs(0.2*x));

 z = (cos(x)) .* cos(sqrt(x.^2 + y.^2)) .* exp(-1*abs(0.2*x));

Best Answer

Related Solutions

MATLAB: How to solve this integration ???

MATLAB: Undefined variable “cos” or class “cos”. Error in P4Afara_Question2 (line 5) z = (cos(x)).*cos(sqrt(x.^2 + y.^2)).exp​(-1*abs(0.​2*x));

Related Question

MATLAB: Undefined variable “cos” or class “cos”. Error in P4Afara_Question2 (line 5) z = (cos(x)).cos(sqrt(x.^2 + y.^2)).exp(-1abs(0.2*x));