MATLAB: I get the error while trying to convert a matlab code to HDL code by Matlab HDL coder.. the error is ‘HDL Code generation does not support 2D-matrices as function inputs’..i’ll grateful if anyone solve this error..

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clc;
clear all;
close all;
image1=imread('cameraman.tif');
subplot(2,2,1);
figure(1);
imshow(image1);title('original image');
image2=stdfilt(image1);  
subplot(2,2,2);
imshow(image2,[]);
title('standard deviation map');
t2=0.1*max(max(image2));
for i=1:256
    for j=1:256
%         c1(:,:,i)=cell2mat(C(i));
%         p1(:,:,i)=cell2mat(P(i));
%         sum1=sum(sum(c1(:,:,i)));
          if image2(i,j) < t2
             s(i,j)=0;
          else
             s(i,j)=1;
          end
      end
  end
  subplot(2,2,3); 
  imshow(s); 
  title('binarized standard deviation map');
%# desired number of horizontal/vertical tiles to divide the image into
numBlkH = 4;
numBlkW = 4;
%# compute size of each tile in pixels

[imgH,imgW,~] = size(s);
szBlkH = [repmat(fix(imgH/numBlkH),1,numBlkH-1) imgH-fix(imgH/numBlkH)*(numBlkH-1)];
szBlkW = [repmat(fix(imgW/numBlkW),1,numBlkW-1) imgW-fix(imgW/numBlkW)*(numBlkW-1)];
%# divide into tiles, and linearize using a row-major order

C = mat2cell(s, szBlkH, szBlkW)';
C = C(:);
%# display tiles i subplots

figure
for i=1:numBlkH*numBlkW
    subplot(numBlkH,numBlkW,i), imshow( C{i} )
end
image1=imread('cameraman.tif');
numBlkH = 4;
numBlkW = 4;
%# compute size of each tile in pixels
[imgH,imgW,~] = size(image1);
szBlkH = [repmat(fix(imgH/numBlkH),1,numBlkH-1) imgH-fix(imgH/numBlkH)*(numBlkH-1)];
szBlkW = [repmat(fix(imgW/numBlkW),1,numBlkW-1) imgW-fix(imgW/numBlkW)*(numBlkW-1)];
%# divide into tiles, and linearize using a row-major order
P = mat2cell(image1, szBlkH, szBlkW)';
P = P(:);
 %# display tiles i subplots
for i=1:numBlkH*numBlkW
    subplot(numBlkH,numBlkW,i), imshow( P{i} )
end
figure
a=1;b=1;
for i=1:16
        c1(:,:,i)=cell2mat(C(i));
        p1(:,:,i)=cell2mat(P(i));
        sum1=sum(sum(c1(:,:,i)));
        t(:,:,i)=sum1/(64*64);
        if t(:,:,i)< 0.5
            poortext(:,:,a)=c1(:,:,i);
            poortext1(:,:,a)=im2double(p1(:,:,i));
            a=a+1;
        else
            text(:,:,b)=c1(:,:,i);
            text1(:,:,b)=p1(:,:,i);
              b=b+1;
          end
  end
    for i=1:a-1
        d=(poortext1(:,:,i));
        subplot(4,4,i)
        imshow(d);
        title('poor-texture');
    end
     figure
    for i=1:b-1
        d1(:,:,i)=(text1(:,:,i));
        d2=d1(:,:,i);
        subplot(4,4,i)
         imshow(d2);
         title('texture');
    end 
  %  figure
    k2=1;
  for i=1:b-1
      [ll,lh,hl,hh]=dwt2(d1(:,:,i), 'haar');
   llc(:,:,k2)=(ll);
  %  subplot(2,2,1);
  %  imshow(llc);
  %  title('LL');
   lhc(:,:,k2)=(lh);
  %  subplot(2,2,2);
  %  imshow(lhc);
  %  title('LH');
   hlc(:,:,k2)=(hl);
  %   subplot(2,2,3);
  %   imshow(hlc);
  %   title('HL');
   hhc(:,:,k2)=(hh);
  %   subplot(2,2,4);
  %   imshow(hhc);
  %   title('HH');
  %   figure
  k2=k2+1;
   end
  figure
  imag1 = imread('peppers.png');imag2=rgb2gray(imag1);
  imag3= imresize(imag2, [64, 64]);
  imshow(imag3);
  figure
  ima=arnold(imag3,24);
  imshow(mat2gray(ima));

Best Answer

You cannot generate HDL for that code. HDL does not have "clear" or "imread" or any plotting of any form.
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