MATLAB: I don’t understand

92%acceptanceadmittanceeligiblegradeshomeworkif statement

hi,

i was asked to write a simple function for home work :

this was my code:

function [admit]=eligible(v,q)
avg=(v+q)/2;
if (avg>=92) && (v>88) && (q>88)
    admit=1;
else
    admit=0;
end
end

and i don't understand why i got this error message :

please advise what is the problem.

thank's

Best Answer

Replace 1 with ~0 and 0 with ~1.

Related Solutions

MATLAB: How to overcome the error “variable admit must be of data type logical instead of double”..I have to return logical values true or false using the function below.what is wrong with this

The error message must have come from somewhere else, not from this function. Here, nothing is wrong except that the data type of "admit" seems not to comply with the required "logical" data type required by somewhere else.

You can use admit=ture, admit=false. "true" and "false" are defined in MATLAB.

MATLAB: How do you have a logical operator of true and false as your type but 0 and 1 as your value

You used mean() incorrectly. Look at this:

>> mean(10,30) % WRONG!
ans =
    10
>> mean([10,30]) % Right way uses brackets.
ans =
    20

So instead of

      if mean(v, q)>= 92 && v>88 && q>88 
           fprintf('true\n');
      elseif mean(v, q)<92 
           fprintf('false\n');
      elseif v<=88 
           fprintf('false\n');
      elseif q<=88
          fprintf('false\n');

use

      if mean([v, q]) >= 92 && v > 88 && q > 88 
           fprintf('true\n');
           isEligible = true;
      else
           fprintf('false\n');
           isEligible = false;
      end

Best Answer

Related Solutions

MATLAB: How to overcome the error “variable admit must be of data type logical instead of double”..I have to return logical values true or false using the function below.what is wrong with this

MATLAB: How do you have a logical operator of true and false as your type but 0 and 1 as your value

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