MATLAB: I am unable to get display of each iteration!! please HELP

iterationMATLAB

i am unable to get display of each iteration!! please HELP

clc;
clear variables;
x=[0;0];
     for iter=1:30
    for i=1:99
    x(1)=4+x(2);
    x(2)=0.5*(1-x(1));
    end
    
           disp(['iter',num2str(iter),';value= ',num2str(x)]);
     end

Best Answer

Your x is a column vector. num2str(x) has two rows. But 'value= ' only has one row, and you cannot [] together one row with two rows.

If you were to use num2str(x.') then that would work out.

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MATLAB: How to output all these row vectors into a matrix

You just need to store your x values inside the loop in an array. Anyway, firstly when you write

v(1)=2; v(2)=0; v(3)=1; v(4)=4; v(5)=2; v(6)=8; v(7)=0;

you are already creating a vector so you don't need the line that follows. Or you could simply write

v = [2 0 1 4 2 8 0];

Both mean the same thing.

Nextly, you could save the given values like,

x_init=[v(5)+1;v(6)]; %This is the first value of x (x(0)) that was given in the question
MaxNorm=0.01; %The length of the vector could not be smaller than 0.01

and then define iter as 1 to calculate the first iteration outside the loop like,

iter=1; 
x(:,iter) = A*x_init;

and then go inside the loop to calculate the remaining iterations until the condition is satisfied,

while norm(x(:,iter))>=MaxNorm
    iter=iter+1; %Count the number of iterations
    x(:,iter)=A*x(:,iter-1);
end

finally, transpose the matrix using,

x = x.';

then plot or do whatever you want to do with it,

plot(x)

MATLAB: Display parameter values at each iteration in the optimization

Use an OutputFcn in the options structure.

Best Answer

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