Hi, I have a problem. This is my program text.
for i=1:614 if (x1(i,1) == 0) p=[1 0 0 0 0 0 0 0 0 0 0 0]; elseif ((x1(i,1) > 0) && (x1(i,1) <= 10000)) p=[0 1 0 0 0 0 0 0 0 0 0 0]; elseif ((x1(i,1) > 10000) && (x1(i,1) <= 20000)) p=[0 0 1 0 0 0 0 0 0 0 0 0]; elseif ((x1(i,1) > 20000) && (x1(i,1) <= 30000)) p=[0 0 0 1 0 0 0 0 0 0 0 0]; elseif ((x1(i,1) > 30000) && (x1(i,1) <= 40000)) p=[0 0 0 0 1 0 0 0 0 0 0 0]; elseif ((x1(i,1) > 40000) && (x1(i,1) <= 50000)) p=[0 0 0 0 0 1 0 0 0 0 0 0]; elseif ((x1(i,1) > 50000) && (x1(i,1) <= 60000)) p=[0 0 0 0 0 0 1 0 0 0 0 0]; elseif ((x1(i,1) > 60000) && (x1(i,1) <= 70000)) p=[0 0 0 0 0 0 0 1 0 0 0 0]; elseif ((x1(i,1) > 70000) && (x1(i,1) <= 80000)) p=[0 0 0 0 0 0 0 0 1 0 0 0]; elseif ((x1(i,1) > 80000) && (x1(i,1) <= 90000)) p=[0 0 0 0 0 0 0 0 0 1 0 0]; elseif ((x1(i,1) > 90000) && (x1(i,1) <= 100000)) p=[0 0 0 0 0 0 0 0 0 0 1 0]; elseif (x1(i,1) > 100000) p=[0 0 0 0 0 0 0 0 0 0 0 1]; else end D=p*Pend
x1 is [614×1] vector.
P is [12×12] matrix.
So with this program my answer is vector D, given 614 times (because x1 have 614 elements). But I need that those vectors would be combine into [614×12] one matrix.
How can I do that? it very urgent.
Best Answer