MATLAB: How to use loops to model a function of displacement changing with respect to angle over time

loop

I have been trying to model the function of displacement (as you can see here: https://i.imgur.com/s6PXKSx.png). To do this I was trying to do a loop function on MATLAB, with a step size of 1/36th of a second from 0s to 1s.
Here is my code so far:
clear all
%recorded constants
h = 60;
b = 130; 
r = 135;
w = 2*pi; % angular velocity 
i=1;
for t =0:(1/36):1 % Starts from 2s with a step size of 2 until 60s
t2(i+1) = t; %Time function to progress with 1 step intervals
x(i+1)=b*((r*sin(wt)/((h-r)*cost(wt))
i=i+1;
end

Best Answer

You have a few typos in your implementation and you do not need a for loop either. Here is the code;
h = 60;
b = 130; 
r = 135;
w = 2*pi; % angular velocity 
t =0:(1/36):1;
x = b*(r*sin(w*t))./(h-r*cos(w*t));
I recommend you insert the picture to your question next time using "image" icon, which makes it easier to answer the question.
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