MATLAB: How to use linear interpolation to fill gaps to generate a contour (closed surface)

MATLAB C/C++ Math LibraryMATLAB Compilermatlab guimatrix manipulation

M = 0 0 0
    0 0 3
    0 3 3
    3 3 3
    0 0 0
    0 0 3
    3 0 0
    0 0 0
    
%  in the first colmn, btween 4th & 7th rows, i wan to fill 3. in the last column, between 4th and 6th i want to fill 3.
X = ~all(M==0,2)
N = interp1(find(X),M(X,:), 'nearest')
% its not giving me solution.

i am focusing only first and last column to generate controur (closed surface )

Plz need some tips.

your cooperation is highly appreciated.

warm regards

Best Answer

"i am focusing only first and last column..."

M = [0 0 0;...
     0 0 3;...
     0 3 3;...
     3 3 3;...
     0 0 0;...
     0 0 3;...
     3 0 0;...
     0 0 0];
Constant = 3; % example value
f = find(M(:,1));
fx = f .* [true;false(numel(f)-1,1)];
M(setdiff(nonzeros(fx):max(f),f),1) = Constant;
l = find(M(:,end));
lx = l .* [true;false(numel(l)-1,1)];
M(setdiff(nonzeros(lx):max(l),l),end) = Constant

Related Solutions

MATLAB: How to manipulate a matrix under certain conditions to fills gaps with numbers.

Let MM - your 'required colum'.

MM =[3,3,0,0,3,3,0,0,0,3,3,0,0,3,3,0,0,3,0]';
 
m = MM;
m(m == 0) = nan;
%lo - define the indices of the values that need to be changed: 
lo = fillmissing(m,'previous') == 3 & fillmissing(m,'next') == 3 & isnan(m); 
% ii - assign numbers to intervals:
ii = cumsum([0;diff(lo)>0]).*lo; 
%{
p - count the amount of each value of vector ii:
1 element -  the number of zeros (0's);
2 element the number of values in the first interval.
3 element the number of values in the second interval, etc.:
%}
p = accumarray(ii(:)+1,1);
% Let a - the values for to be changed (vector with length equal max(ii), in our case - 4):
a = [3,4,4,3]'; % HERE fixed..
% Condition for intervals with length equal 1
a(p == 1) = 3;
% Replacement:
MM(lo) = a(ii(lo));

MATLAB: How to fill gaps in a matrix with a numbers using interpolation to develop a contour.

M(cumsum(M) & cumsum(M,1,'reverse')) = 3;

or for:

M =[0 0 0; 2 2 3; 3 3 0; 0 0 0; 3 3 0; 2 2 3; 0 0 0; 3 3 2; 0 0 0; 3 3 3];
s = join(string(M)','');
[a,b] = regexp(s,'30+3');
lo = false(size(M));
for ii = 1:numel(a)
    for jj = 1:numel(a{ii})
        lo(a{ii}(jj)+1:b{ii}(jj)-1,ii) = true;
    end
end
M(lo) = 3;

Best Answer

Related Solutions

MATLAB: How to manipulate a matrix under certain conditions to fills gaps with numbers.

MATLAB: How to fill gaps in a matrix with a numbers using interpolation to develop a contour.

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