MATLAB: How to understand pdeplot3D

Question

Hi all,
I'm trying to run this example from help of function pdeplot3D:
    structuralmodel = createpde('structural','static-solid');
    importGeometry(structuralmodel,'SquareBeam.STL');
    structuralProperties(structuralmodel,'PoissonsRatio',0.3, ...
        'YoungsModulus',210E3);
    structuralBC(structuralmodel,'Face',6,'Constraint','fixed');
    structuralBoundaryLoad(structuralmodel,'Face',5,'SurfaceTraction',[0;0;-2]);
    generateMesh(structuralmodel);
    structuralresults = solve(structuralmodel);
    pdeplot3D(structuralmodel,'ColorMapData',structuralresults.VonMisesStress, ...
        'Deformation',structuralresults.Displacement)

In the variable 'structuralresults', I noticed this:

>> structuralresults.Displacement
ans = 
    struct with fields:
             ux: [7841×1 double]
             uy: [7841×1 double]
             uz: [7841×1 double]
      Magnitude: [7841×1 double]

What is the Magnitude here? As far as I understand ux, uy, uz already denotes the deformations.

Answer 1

magnitude = square root (ux^2 +uy^2+ uz^2). You can verify this through the following command:

>>a = sqrt((structuralresults.Displacement.ux.^2)+(structuralresults.Displacement.uy.^2)+(structuralresults.Displacement.uz.^2));

Values in "a" will match with those in the filed "Magnitude".