if true % code
while r<((M*N)+1) for i=1:M for j=1:N k(r)=imag1(i,j); l(r)=k(r); b(r)=de2bi(k(r)); r=r+1; end end
The de2bi(k(r)) is '10010101' but whether it is possible to store this 8 bit value as k(1)=1 k(2)=0 k(3)=0 … … k(8)=1
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