Hi I am trying to solve the following equation: Eqn = (a/2)*log((Rs+a)/(Rs-a))== Ind; I can solve it for individual values of Ind using the functions solve as follows:
Ind = 13;Rs = 5;syms aEqn = (a/2)*log((Rs+a)/(Rs-a))== Ind;Sol = solve(Eqn,a);
The problem comes when Ind data are stored in a cell array cell(1,n) and each cell contains (m x n) arrays. I would like to solve the equation for the first column of the array contained at each cell and organize the solution also in a cell array where sol{i}(1:end) comes from Ind{i}(1:end,1) I have tried:
Ind = cell(1,10);Sol = cell(1,10);Eqn = cell(1,10); for i = 1:10 Ind{i} = (0:3:15)'; end Rs = 5; for i = 1:10 syms a Eqn{i} = (a/2)*log((Rs+a)/(Rs-a))== Ind{i} Sol{i} = solve(Eqn{i},a); end
But of course it does not work. I have also tried other combination and even indexing the data with two for loops taking i and j for numbering cell number and row but I just have no idea how to treat these kind of data. Thanks a lot in advance for any advice!!!
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