MATLAB: How to solve dm/dt = R(1-A) – B (A) in MATLAB

equation

I have this equation:

dm/dt = R(1-A) - B (A)

I need to solve A when:

dmdt= 0
R =0.1
B= 0.2

I am able to solve it by hand, but how can I solve this problem in MATLAB? Can I set this as a function?

If you have the symbolic toolbox,

syms A
R = 0.1
B = 0.2
Asol = solve( R*(1-A)-B*A, A)

The big advantage of Answers is the ability to edit what you've posted. I use that feature a lot.

A few errors: no * after the 2, a square bracket instead of parenthesis, and ln instead of log. Corrected code:

A = 1/3;
N =10;
c= 0;
Kon= 0.5;
Koff = 0.02;
m = 2* (1 - (log(1/A)-1)/N + log( (1+(c/Kon))/1+(c/Koff)))

In the command window:

m =
          1.98027754226638