You have what you claim to be a linear system of 7 equations in 7 unknowns. (I've not checked this claim, carefully, but it looks to be true from a quick glance.)
If you write the system in the form A*x = b, the matrix A is full rank, yet the right hand side is all zero.
Sorry. Basic linear algebra here. There exists only ONE solution to your problem. It is the all zero solution. Nothing you can do will yield a different solution, if the situation is as I have described it. I'm not sure I would say anything caused this result, at least not beyond linear algebra 101.
Why do I say there is no solution as you want? A square matrix that is full rank means that NO non-trivial linear combination of the columns will produce a zero vector. Yet, you are looking for a linear combination of the columns of A that results in b, a zero vector. (Think about what it means to multiply the matrix A by a vector x.) So the only solution is the trivial one: all zeros. It is unique.
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