MATLAB: How to reshape each matrix of cell

matrixmatrix arraymatrix manipulation

Hello.

I want to reshape each matrix of cell.

Using this code, I got the cell matrix. How can I reshape the matrix (1325 x180) to (25 x 9540)?

clear all
close all
% Create the list of csv files 
s = dir('*.csv');
% Read from each csv file 
c = cell(numel(s),1 ); 
for kk = 1:numel(s ) 
filePath = fullfile(s(kk).folder,s(kk).name ); 
x = csvread(filePath ); 
c{kk} = x; 
end
% Find the minumul number of row and column 
row = cellfun(@(x) size(x,1),c ); 
col = cellfun(@(x) size(x,2),c ); 
minRow = min(row ); 
minCol = min(col);
% Adjust the size of each array to minRow-by-minCol 
c = cellfun(@(x) x(1:minRow,1:minCol),c,'UniformOutput',false);
% How to reshape (1325 x180) to (25 x 9540) ?

Best Answer

for k=1:length(c)
c{k}=reshape(c{k},25,9540);
end

Related Solutions

MATLAB: How to flatten and split and concatenate arrays in several files

I think the following code can do that task:

By the way, your code will output 28440-by-1 (28440 = 9480 x 3), not the 3-by-9480. So the following code will generate N-by-1 array.

% Create the list of csv files
s = dir('boxing/*.csv');
% Read from each csv file
c = cell(numel(s),1);
for kk = 1:numel(s)
  filePath = fullfile(s(kk).folder,s(kk).name);
  x = csvread(filePath);
  c{kk} = x(:);
end
% Find the minumul length
len = cellfun(@numel,c);
minLen = min(len);
% Delete minLen+1:end for each array in cell
c = cellfun(@(x) x(1:minLen),c,'UniformOutput',false);
% Concatenate them
All = cell2mat(c);

MATLAB: How to find the minimum number of row and column and concatenate to a matrix

Don't you need the minimum dimension in order to concatenate? In other words, you need to find the max dimensions. Untested code:

minRequiredRows = 0;
minRequiredColumns = 0;
for k = 1 : length(Phi_NuMax)
    thisMatrix = Phi_NuMax{k};
    [thisRows, thisColumns] = size(thisMatrix);
    fprintf('Cell #%d has %d rows and %d columns.\n', k, thisRows, thisColumns);
    % Find out how wide the matrix will need to be if they are all stacked on top of one another.
    minRequiredColumns = max(minRequiredColumns, thisColumns);
    % Sum up how many rows we'll need to hold all of them vertically.
    minRequiredRows = minRequiredRows + thisRows; 
end
fprintf('At a minimum, you will require %d rows and %d columns.\n', k, minRequiredRows, minRequiredColumns);
% Now instantiate a matrix for all the individual matrices stitched together vertically.
allMatrixes = zeros(minRequiredRows, minRequiredColumns);
% Now concatenate by inserting the cell into all Matrixes at the appropriate row number.
currentRow = 1;
for k = 1 : length(Phi_NuMax)
    thisMatrix = Phi_NuMax{k};
    [thisRows, thisColumns] = size(thisMatrix);
    fprintf('Inserting cell #%d with %d rows and %d columns.\n', k, thisRows, thisColumns);
    allMatrixes(currentRow : currentRow + thisRows - 1, 1:thisRows) = thisMatrix;
    % Move the pointer to the next place where we will insert the next matrix.
    currentRow = currentRow + thisRows;
end

Best Answer

Related Solutions

MATLAB: How to flatten and split and concatenate arrays in several files

MATLAB: How to find the minimum number of row and column and concatenate to a matrix

Related Question